How to program a delay in Swift 3

Matheus Mello
Matheus Mello
September 2, 2023
Cover Image for How to program a delay in Swift 3

How to Program a Delay in Swift 3: Solving the Dispatcher Dilemma 🕐🚀

Have you ever needed to create a delay before running a sequence of code in Swift 3? 🤔

In earlier versions of Swift, the solution was as simple as using the dispatch_after function. However, with the introduction of Swift 3 and Xcode's automatic code migration, a common problem arises: the dreaded "Cannot convert DispatchTime.now to expected value dispatch_time_t aka UInt64" error. 😱

But fear not, fellow developers! We have come to your rescue with an easy and straightforward solution to this dilemma. 👊💥

The Obstacle: Dispatcher vs. DispatchTime ⏲️❌⌛

In Swift 3, the dispatch_ prefix has been replaced with Dispatch for improved readability and clarity. This shift has led to changes in code that once worked like a charm. 😢

Before diving into the solution, let's quickly recap how we used to create a delay in earlier versions of Swift:

let time = dispatch_time(dispatch_time_t(DISPATCH_TIME_NOW), 4 * Int64(NSEC_PER_SEC))
dispatch_after(time, dispatch_get_main_queue()) {
    //put your code which should be executed with a delay here
}

This code served us well until we migrated to Swift 3, where Xcode automatically refactors the code in 6 different ways. Unfortunately, this refactoring unexpectedly generates an error. 🙅‍♂️❌

The Solution: The Awaited Dispatch 🤞✨

So, how do we create a delay in Swift 3 without encountering the "Cannot convert" error? 🤔

The answer lies in embracing the new Swift 3 syntax and using the DispatchQueue class, specifically its asyncAfter method. This method allows us to execute a block of code after a specified delay. 💡📝

Here's the updated and correct syntax for Swift 3:

DispatchQueue.main.asyncAfter(deadline: .now() + 4) {
    //put your code which should be executed with a delay here
}

Now, isn't that sleek and concise? 🤗

Putting It All Together: Solving the Delay Dilemma 🔄🔁

To summarize, here's a step-by-step guide to creating a delay in Swift 3:

  1. Replace the old dispatch_time function with DispatchQueue.main.asyncAfter.

  2. Use the deadline parameter and set it to .now() + <desired delay>.

  3. Insert your code within the closure that follows the asyncAfter method.

With these changes, you'll be able to create a delay and execute your code without any errors. 🎉

Join the Delay Party! 🎈🎊

Now that you've mastered the art of creating a delay in Swift 3, it's time to put your newly acquired knowledge into action! 💪

Challenge yourself to find creative ways to leverage delays in your projects and share your experiences with us in the comments below. 📝 We can't wait to hear about your exciting delay-driven adventures! 🚀

Happy coding! 😊👩‍💻👨‍💻

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