Check if String contains at least one Number in JavaScript

Check assuming that String contains Numbers #

Utilize the RegExp.test() strategy to check in the event that a string contains no less than one number, for example /\d/.test(str). The test strategy will return valid if the string contains no less than one number, generally bogus will be returned.

index.js

const str1 = 'hi 42 world';
const str2 = 'hi world';

function containsNumber(str) {
  return/\d/.test(str);
}

console.log(containsNumber(str1));//👉️ valid
console.log(containsNumber(str2));//👉️ bogus

We utilized the RegExp.test strategy to check assuming the string contains numbers.

The forward slashes / / mark the beginning and end of the regular expression.

The \d character matches any digit from 0 to 9.

In the event that you at any point need assistance perusing a normal articulation, look at this regex cheatsheet from MDN.

The test() strategy returns valid on the off chance that the standard articulation is matched in the string, generally bogus is returned.

Alternatively, you can use the [0-9] range. This may be more readable if you're not familiar with the special characters in regular expressions.

The accompanying model likewise checks in the event that a string contains no less than one number.

index.js

const str1 = 'hi 42 world';
const str2 = 'hi world';

function containsNumber(str) {
  return/[0-9]/.test(str);
}

console.log(containsNumber(str1));//👉️ valid
console.log(containsNumber(str2));//👉️ bogus

Instead of using the \d special character, we used the [0-9] character class.

This character class is utilized to determine a scope of numbers that we need to match.

The [0-9] territory ought to be a smidgen more discernible than the \d character in the event that you're curious about normal articulations.

Further Perusing

• Check assuming String contains just Letters and Spaces in JS

• Check assuming that letter in String is Capitalized or Lowercase in JS